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المرحلة 2
أستاذ المادة كريم عباس لايذ الغرابي
12/07/2018 17:53:46
The concept of set is fundamental in groups , so we briefly some notions about sets , functions , and number theory . The student study this subjects , so we will briefly summarizes of it . Definition 1 – 1 . If A is an arbitrary set , then the set whose elements are all the subsets of A is known as the POWER SET of A and denoted by P (A) : P (A) = { B ?B ?A } . Example: If A = { a , b } , find P ( A ) . Solution : H . W .
Notes: If A is a finite set with n elements , then P ( A ) having 2n element s . P ( A ) ? ? Definition 1 – 2 . The CARTESIAN PRODUCT of two nonempty sets A and B , denoted by A × B , is the set A ×B = { (a,b) ?a ? A and b ? B } Definition 1 – 3 . Let A be a nonempty set , a subset R of the Cartesian product A × A is called RELATION .
1 Definition 1 – 4 . A relation R in a set A is said to be an EQUIVALENCE RELATION in A provided it satisfied the properties , reflexive: aRa , for each a ? A , symmetric : if aRb for some a, b ? , then b R a , transitive : if aRb and bRc for some a , b , c ? A , then aRc . Equivalence relations are denoted by ~ . Example . Let A be the set of all lines in a plane . For a , b ? A let a ? ? b means that a is parallel to b .If we agree that every line is parallel to itself , then ? ? is equivalence relations . Definition 1 – 5 . Let Z be the set of integer numbers , and let n be a fixed positive integer . For any a , b ? Z , a is said to be congruent to be (modulo n), written a ? b (mod n), if and only if the deference a – b is divisible by n. that is mean , a ? b (mod n), if and only if a – b = kn for some integer n. Example. If n =5, we note 2 ? 7 ( mod 5) -1 ? 4 ( mod 5) Definition 1-6 . Let ~ be an equivalence relations on A , and let a ? A . The set of all elements in A which are equivalent to a is called the EQUIVALENCE CLASS of a under ~ and is denoted by [ a ] : [ a ] = { b ?A? b ~ a } . 2 Theorem 1-1. Let ~ be an equivalence relation in the set A . Then, 1)for each a ? A , [ a ] ? ? , 2) if b ? [ a ] , then [ a ] = [ b ] , 3) for any a , b ? A , with [a ] ? [ b ] , [ a ] ? [ b ] =? , 4) U { [ a ] | a ? A } = A . Proof . ~ is equivalence relation , so it is reflexive . a ~ a , then a ? [ a]. Hence [a] ? ? Let b? [a], Hence b ~ a . Since ~ is symmetric , then a ~ b. Suppose that x ? [a], then x~a . Since ~ is transitive , then x ~ b. Hence x ? [b] . So [a] ? [b]. Similarly [b] ? [a] suppose that [a] ? [b] ? ?, So there exist c ? [a] ? [b]. By 2 [a] = [c] = [b] , which is contradiction . So [a] ? [b] = ?. Since [a] ? A , then U {[a]|a ? A } ? A. Since for each a ? A, then a ? [a]. Hence A ? U{[a] | a? A }. So U{[a] |a? A } = A Definition 1 - 7 .
A partition of a set A is a family {Ai} of nonempty subsets of A with the properties If Ai ? Aj , then Ai ? Aj = ? (pairwise disjoint), U Ai = A. Example If Zeis the set of even integers, andZo is the set of odd integers, thenZeU Zo = Z, andZe ? Zo = ?. Hence {Ze ,Zo} is partition of Z. Example. If A = { 0 ,1, 2 , . . . , 24 } , n= 5 , then { [ 0 ] , [ 1 ] , [ 2 ] , [ 3 ] , [ 4 ] } is partition of A.
Theorem 1-2 . If {Ai} is a partition of the set A, then there is an equivalence . relation in A whose equivalence classes are precisely the . sets Ai.
المادة المعروضة اعلاه هي مدخل الى المحاضرة المرفوعة بواسطة استاذ(ة) المادة . وقد تبدو لك غير متكاملة . حيث يضع استاذ المادة في بعض الاحيان فقط الجزء الاول من المحاضرة من اجل الاطلاع على ما ستقوم بتحميله لاحقا . في نظام التعليم الالكتروني نوفر هذه الخدمة لكي نبقيك على اطلاع حول محتوى الملف الذي ستقوم بتحميله .
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